WebFeb 27, 2024 · 那么思路是这样的:我们输入一个特殊的以“0e”开头的数字字符串,这个字符串经过md5计算后的值也为以“0e”开头的数字字符串,最终要达到的效果类似这样: "0e123456"="0e+30位数字" 从而可以拿到flag Talk is cheap,show me the code. 它经过md5计算后为0e291242476940776845150308577824 符合要求 JSON绕过 代码逻辑是 … WebJun 9, 2024 · Roughly 1 in every 256 MD5 hashes will start with '0e', and the probability that the remaining 30 characters are all digits is (10/16)^30. If you do the maths, you'll find …
[CTF]CTF中if (md5(md5($_GET[‘a’])) == md5($_GET[‘b’])) 的绕过
WebMar 22, 2024 · CTF中MD5考点总结 MD5 CTF 发布日期: 2024-03-22 更新日期: 2024-04-10 阅读次数: 1.最基础的 0e绕过 原理: 0e开头且都是数字的字符串,弱类型比较都等于0 - QNKCDZO - 240610708 - s878926199a - s155964671a - s214587387a - s214587387a 这些字符串的 md5 值都是 0e 开头,在 php 弱类型 比较中判断为相等 2.数组绕过 无论是弱 … WebMar 17, 2024 · 0e在比较的时候会将其视作为科学计数法,所以无论0e后面是什么,0的多少次方还是0。 所以只要让a和b在经过相应的函数加密之后都是以0e开头就可以。 以下是一些md5加密后开头为0e的字符串: five time sit to stand test age norms
php - CTF Type Juggling with ripemd160 hash - Stack …
WebNow we have to concatenate the two message generated by the script with our file and the simpler way is to use cat command: cat msg1 >> input-file. We can check if the files have the same md5 hash: $ md5 a.py b.py MD5 (a.py) = dfe4111466b2d137b23c75a372d05ebd MD5 (b.py) = dfe4111466b2d137b23c75a372d05ebd WebSo, we’re looking for two strings that PHP will incorrectly interpret as numbers, specifically in scientific notation (“0e….") Thankfully someone else already brute-forced this for us, as seen here . WebJun 7, 2024 · The CTF was a mixed bag of challs ,some of them were easy-peasy while some were really tough but above all it was fun. To add to the spice, while the CTF was … five times one fourth